In (int x, int y) -> x + y, what is 'x + y'?

In (int x, int y) -> x + y, what is 'x + y'?

• A. The parameters
• B. The return value
• C. The body of the lambda expression
• D. The type of the expression

Answer: (C)

The thing after the parameter list and the arrow is the body of the lambda—the computation the lambda performs. Here, x and y are the inputs, and x + y is the operation that uses those inputs to produce a result. When the lambda runs, it evaluates x + y and returns that value. So x + y is the body of the lambda, the expression that defines what value gets returned. It’s not the parameters themselves, and it’s not a separate return type; the return value is whatever x + y evaluates to for the given inputs.

The thing after the parameter list and the arrow is the body of the lambda—the computation the lambda performs. Here, x and y are the inputs, and x + y is the operation that uses those inputs to produce a result. When the lambda runs, it evaluates x + y and returns that value. So x + y is the body of the lambda, the expression that defines what value gets returned. It’s not the parameters themselves, and it’s not a separate return type; the return value is whatever x + y evaluates to for the given inputs.